{"id":333,"date":"2022-04-13T10:43:10","date_gmt":"2022-04-13T10:43:10","guid":{"rendered":"http:\/\/10thclass.deltapublications.in\/?page_id=333"},"modified":"2025-01-03T09:12:01","modified_gmt":"2025-01-03T09:12:01","slug":"r-2-central-angles","status":"publish","type":"page","link":"https:\/\/10thclass.deltapublications.in\/index.php\/r-2-central-angles\/","title":{"rendered":"R.2 Central angles"},"content":{"rendered":"\n

Central angles<\/strong><\/h2>\n\n\n\n

Key Notes :<\/p>\n\n\n\n

The measures of the central angles in a circle add up to 360\u00b0.<\/p>\n\n\n\n

\ud83d\udd14 What is \u2220GJH?<\/p>\n\n\n

\n
\"This<\/figure><\/div>\n\n\n

\u2220GJH= ______ \u00b0<\/p>\n\n\n\n

Look at the diagram:<\/p>\n\n\n

\n
\"This<\/figure><\/div>\n\n\n

Write an equation showing that the measures of \u2220GJH, \u2220HJI and \u2220GJI sum to 360\u00b0, since they span an entire circle. Then solve for \u2220GJH.<\/p>\n\n\n\n

\u2220GJH + \u2220HJI + \u2220GJI = 360\u00b0<\/p>\n\n\n\n

\u2220GJH+120\u00b0+90\u00b0 = 360\u00b0 Plug in \u2220HJI=120\u00b0 and \u2220GJI=90\u00b0<\/p>\n\n\n\n

\u2220GJH+210\u00b0 = 360\u00b0 Combine like terms<\/p>\n\n\n\n

\u2220GJH = 150\u00b0 Subtract 210\u00b0 from both sides<\/p>\n\n\n\n

So, \u2220GJH=150\u00b0.<\/p>\n\n\n\n

\ud83d\udd14 What is \u2220QPR?<\/p>\n\n\n

\n
\"This<\/figure><\/div>\n\n\n

\u2220QPR= _____\u00b0<\/p>\n\n\n\n

Look at the diagram:<\/p>\n\n\n

\n
\"This<\/figure><\/div>\n\n\n

Write an equation showing that the measures of \u2220RPS, \u2220QPS and \u2220QPR sum to 360\u00b0, since they span an entire circle. Then solve for \u2220QPR.<\/p>\n\n\n\n

\u2220RPS+\u2220QPS+\u2220QPR = 360\u00b0<\/p>\n\n\n\n

110\u00b0+110\u00b0+\u2220QPR = 360\u00b0 Plug in \u2220RPS=110\u00b0 and \u2220QPS=110\u00b0<\/p>\n\n\n\n

\u2220QPR+220\u00b0 = 360\u00b0 Combine like terms<\/p>\n\n\n\n

\u2220QPR = 140\u00b0 Subtract 220\u00b0 from both sides<\/p>\n\n\n\n

So, \u2220QPR=140\u00b0.<\/p>\n\n\n\n

\ud83d\udd14 What is \u2220GJI?<\/p>\n\n\n

\n
\"This<\/figure><\/div>\n\n\n

\u2220GJI= _____\u00b0<\/p>\n\n\n\n

Look at the diagram:<\/p>\n\n\n

\n
\"This<\/figure><\/div>\n\n\n

Write an equation showing that the measures of \u2220GJI, \u2220HJI and \u2220GJH sum to 360\u00b0, since they span an entire circle. Then solve for \u2220GJI.<\/p>\n\n\n\n

\u2220GJI+\u2220HJI+\u2220GJH = 360\u00b0<\/p>\n\n\n\n

\u2220GJI+140\u00b0+90\u00b0 = 360\u00b0 Plug in \u2220HJI=140\u00b0 and \u2220GJH=90\u00b0<\/p>\n\n\n\n

\u2220GJI+230\u00b0 = 360\u00b0 Combine like terms<\/p>\n\n\n\n

\u2220GJI = 130\u00b0 Subtract 230\u00b0 from both sides<\/p>\n\n\n\n

So, \u2220GJI=130\u00b0.<\/p>\n\n\n\n

Learn with an example<\/strong><\/p>\n\n\n\n

\n
\n

What is \u2220GFI ?<\/strong><\/p>\n\n\n

\n
\"\"<\/figure><\/div>\n\n\n

\u2220GFI = ______\u00b0<\/strong> <\/p>\n<\/div><\/div>\n\n\n\n

Look at the diagram:<\/p>\n\n\n

\n
\"\"<\/figure><\/div>\n\n\n

Write an equation showing that the measures of \u2220GFH,\u2220GFI and \u2220HFI sum to 360\u00b0, since they span an entire circle. Then solve for \u2220GFI.<\/p>\n\n\n\n

\u2220GFH + \u2220GFI + \u2220HFI = 360\u00b0<\/p>\n\n\n\n

150\u00b0 + \u2220GFI + 80\u00b0<\/strong> = 360\u00b0 Plug in <\/em>\u2220GFH = 150\u00b0 and <\/em> \u2220HFI = 80\u00b0<\/strong><\/p>\n\n\n\n

\u2220GFI + 230\u00b0 = 360\u00b0 Combine like terms<\/p>\n\n\n\n

\u2220GFI = 130\u00b0 Subtract 230\u00b0 from both sides<\/p>\n\n\n\n

So, \u2220GFI = 130\u00b0 <\/p>\n<\/div><\/div>\n\n\n\n

\n
\n

What is \u2220RQS?<\/strong><\/p>\n\n\n

\n
\"\"<\/figure><\/div>\n\n\n

 \u2220RQS = _______\u00b0<\/strong> <\/p>\n<\/div><\/div>\n\n\n\n

Look at the diagram:<\/p>\n\n\n

\n
\"\"<\/figure><\/div>\n\n\n

Write an equation showing that the measures of \u2220RQS , \u2220RQT and \u2220SQT sum to 360\u00b0, since they span an entire circle. Then solve for \u2220RQS.<\/p>\n\n\n\n

\u2220RQS + \u2220RQT + \u2220SQT = 360\u00b0<\/p>\n\n\n\n

\u2220RQS+ 140\u00b0 + 120\u00b0<\/strong> = 360\u00b0 Plug in \u2220RQT = 140\u00b0 and <\/em> \u2220SQT = 120\u00b0<\/strong><\/p>\n\n\n\n

\u2220RQS + 260\u00b0 = 360\u00b0 Combine like terms<\/p>\n\n\n\n

\u2220RQS = 100\u00b0 Subtract 260\u00b0 from both sides<\/p>\n\n\n\n

So, \u2220RQS = 100\u00b0 <\/p>\n<\/div><\/div>\n\n\n\n

\n
\n

What is \u2220IHJ?<\/strong><\/p>\n\n\n

\n
\"\"<\/figure><\/div>\n\n\n

\u2220IHJ = _______\u00b0<\/p>\n<\/div><\/div>\n\n\n\n

Look at the diagram:<\/p>\n\n\n

\n
\"\"<\/figure><\/div>\n\n\n

Write an equation showing that the measures of \u2220IHK , \u2220JHK and \u2220IHJ sum to 360\u00b0, since they span an entire circle. Then solve for \u2220IHJ.<\/p>\n\n\n\n

\u2220IHK + \u2220JHK + \u2220IHJ= 360\u00b0<\/p>\n\n\n\n

140\u00b0 + 80\u00b0<\/strong> +\u2220IHJ = 360\u00b0 Plug in \u2220IHK = 140\u00b0 and <\/em> \u2220JHK  = 80\u00b0<\/strong><\/p>\n\n\n\n

\u2220IHJ + 220\u00b0 = 360\u00b0 Combine like terms<\/p>\n\n\n\n

\u2220IHJ = 140\u00b0 Subtract 220\u00b0 from both sides<\/p>\n\n\n\n

So, \u2220IHJ= 140\u00b0 <\/p>\n<\/div><\/div>\n\n\n\n

let’s practice!<\/p>\n\n\n\n

\n
\n
\"\"<\/a><\/figure>\n<\/div>\n\n\n\n
\n
\"\"<\/a><\/figure>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

Central angles Key Notes : The measures of the central angles in a circle add up to 360\u00b0. \ud83d\udd14 What is \u2220GJH? \u2220GJH= ______ \u00b0 Look at the diagram: Write an equation showing that the measures of \u2220GJH, \u2220HJI and \u2220GJI sum to 360\u00b0, since they span an entire circle. Then solve for \u2220GJH. \u2220GJH + \u2220HJI + \u2220GJI = 360\u00b0 \u2220GJH+120\u00b0+90\u00b0 = 360\u00b0 Plug in \u2220HJI=120\u00b0 andContinue reading “R.2 Central angles”<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-333","page","type-page","status-publish","hentry","entry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/333","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/comments?post=333"}],"version-history":[{"count":13,"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/333\/revisions"}],"predecessor-version":[{"id":17354,"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/333\/revisions\/17354"}],"wp:attachment":[{"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/media?parent=333"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}