{"id":160,"date":"2022-04-13T10:11:53","date_gmt":"2022-04-13T10:11:53","guid":{"rendered":"http:\/\/10thclass.deltapublications.in\/?page_id=160"},"modified":"2025-01-18T09:51:09","modified_gmt":"2025-01-18T09:51:09","slug":"h-10-multiply-two-binomials","status":"publish","type":"page","link":"https:\/\/10thclass.deltapublications.in\/index.php\/h-10-multiply-two-binomials\/","title":{"rendered":"H.10 Multiply two binomials"},"content":{"rendered":"\n

Multiply two binomials<\/strong><\/h2>\n\n\n\n

key notes:<\/p>\n\n\n\n

To simplify the product of two binomials, use the distributive property.<\/p>\n\n\n\n

As a shortcut, you can use the FOIL<\/strong> method. Find the products of the F<\/strong>irst, O<\/strong>utside, I<\/strong>nside, and L<\/strong>ast terms, and then add them.<\/p>\n\n\n\n

Learn with an example<\/strong><\/p>\n\n\n\n

\n
\n

\ud83d\udd14 Find the product. <\/p>\n\n\n\n

Simplify your answer.<\/p>\n\n\n\n

(2k + 4) (k + 2)<\/p>\n<\/div><\/div>\n\n\n\n

Use the distributive property to simplify (2k+4)(k+2). You can use the FOIL method:<\/p>\n\n\n\n

Multiply the first terms of (2<\/strong>k+4)(k+2):<\/p>\n\n\n\n

(2k)(k)=2k2<\/sup><\/p>\n\n\n\n

Multiply the outside terms of (2<\/strong>k+4)(k+2<\/strong>):<\/p>\n\n\n\n

(2k)(2)=4k<\/p>\n\n\n\n

Multiply the inside terms of (2k+4<\/strong>)(k+2):<\/p>\n\n\n\n

(4)(k)=4k<\/p>\n\n\n\n

Multiply the last terms of (2k+4<\/strong>)(k+2<\/strong>):<\/p>\n\n\n\n

(4)(2)=8<\/p>\n\n\n\n

Finally, add these results and simplify.<\/p>\n\n\n\n

2k2<\/sup>+4k+4k+8<\/p>\n\n\n\n

2k2<\/sup>+8k+8<\/p>\n<\/div><\/div>\n\n\n\n

\n
\n

\ud83d\udd14 Find the product. <\/p>\n\n\n\n

Simplify your answer.<\/p>\n\n\n\n

(2b+4)(2b\u20133)<\/p>\n<\/div><\/div>\n\n\n\n

Use the distributive property to simplify (2b+4)(2b\u20133). You can use the FOIL method:<\/p>\n\n\n\n

Multiply the first terms of (2<\/strong>b+4)(2<\/strong>b\u20133):<\/p>\n\n\n\n

(2b)(2b)=4b2<\/sup><\/p>\n\n\n\n

Multiply the outside terms of (2<\/strong>b+4)(2b\u20133<\/strong>):<\/p>\n\n\n\n

(2b)(\u20133)=\u20136b<\/p>\n\n\n\n

Multiply the inside terms of (2b+4<\/strong>)(2<\/strong>b\u20133):<\/p>\n\n\n\n

(4)(2b)=8b<\/p>\n\n\n\n

Multiply the last terms of (2b+4<\/strong>)(2b\u20133<\/strong>):<\/p>\n\n\n\n

(4)(\u20133)=\u201312<\/p>\n\n\n\n

Finally, add these results and simplify.<\/p>\n\n\n\n

4b2<\/sup>+\u20136b+8b+\u201312<\/p>\n\n\n\n

4b2<\/sup>+2b\u201312<\/p>\n<\/div><\/div>\n\n\n\n

\n
\n

\ud83d\udd14 Find the product. <\/p>\n\n\n\n

Simplify your answer.<\/p>\n\n\n\n

(3u\u20133)(2u\u20132)<\/p>\n<\/div><\/div>\n\n\n\n

Use the distributive property to simplify (3u\u20133)(2u\u20132). You can use the FOIL method:<\/p>\n\n\n\n

Multiply the first terms of (3<\/strong>u\u20133)(2<\/strong>u\u20132):<\/p>\n\n\n\n

(3u)(2u)=6u2<\/sup><\/p>\n\n\n\n

Multiply the outside terms of (3<\/strong>u\u20133)(2u\u20132<\/strong>):<\/p>\n\n\n\n

(3u)(\u20132)=\u20136u<\/p>\n\n\n\n

Multiply the inside terms of (3u\u20133<\/strong>)(2<\/strong>u\u20132):<\/p>\n\n\n\n

(\u20133)(2u)=\u20136u<\/p>\n\n\n\n

Multiply the last terms of (3u\u20133<\/strong>)(2u\u20132<\/strong>):<\/p>\n\n\n\n

(\u20133)(\u20132)=6<\/p>\n\n\n\n

Finally, add these results and simplify.<\/p>\n\n\n\n

6u2<\/sup>+\u20136u+\u20136u+6<\/p>\n\n\n\n

6u2<\/sup>\u201312u+6<\/p>\n<\/div><\/div>\n\n\n\n

let’s practice!\ud83d\udd8a\ufe0f<\/p>\n\n\n\n

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\"\"<\/a><\/figure>\n<\/div>\n\n\n\n
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\"\"<\/a><\/figure>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

Multiply two binomials key notes: To simplify the product of two binomials, use the distributive property. As a shortcut, you can use the FOIL method. Find the products of the First, Outside, Inside, and Last terms, and then add them. Learn with an example \ud83d\udd14 Find the product. Simplify your answer. (2k + 4) (k + 2) Use the distributive property to simplify (2k+4)(k+2). You can use the FOIL method: Multiply the first termsContinue reading “H.10 Multiply two binomials”<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-160","page","type-page","status-publish","hentry","entry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/160","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/comments?post=160"}],"version-history":[{"count":12,"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/160\/revisions"}],"predecessor-version":[{"id":17422,"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/160\/revisions\/17422"}],"wp:attachment":[{"href":"https:\/\/10thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/media?parent=160"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}