Perimeters of similar figures

The following proportion applies to similar shapes:

a/b=p1/p2

where a/b is the ratio of the corresponding side lengths, and p1/p2 is the ratio of the perimeters.

Learn with an example

The figures below are similar. The labelled sides are corresponding.

P2 = _________ millimetres

Find the ratio of the corresponding side lengths.

a / b = 8/4 =2/1

Find the ratio of the perimeters.

p1 / p2 = 48 / p2

Use these two ratios to set up a proportion and solve for P2.

2 / 1 = 48 / p2

2 / 1 (p2) = 48 / p2 (p2) Multiply both sides by P2

2 p2 = 48 .1 Simplify

2 p2 = 48 Simplify

2 p2 ÷  2= 48 ÷ 2 Divide both sides by 2

p2 = 24

The perimeter of the smaller hexagon is 24 millimetres.

The figures below are similar. The labelled sides are corresponding.

P1 = _________ millimetres

Find the ratio of the corresponding side lengths.

a / b = 2/6 =1/3

Find the ratio of the perimeters.

p1 / p2 = p1 / 30

Use these two ratios to set up a proportion and solve for p1.

1 / 3 = p1 / 30

1 / 3 (3 . 30) = p1 / 30 (3 . 30) Multiply both sides by 3 . 30

1 .30 = 3 p1 Simplify

30 = 3 p1 Simplify

30 ÷  3= 3 p1 ÷ 3 Divide both sides by 3

10 = p1

The perimeter of the smaller rectangle is 10 centimetres.

The figures below are similar. The labelled sides are corresponding.

P2 = _________ millimetres

Find the ratio of the corresponding side lengths.

a / b = 9/5

Find the ratio of the perimeters.

p1 / p2 = 45 / p2

Use these two ratios to set up a proportion and solve for P2.

9 / 5 = 45 / p2

9 / 5 ( 5p2) = 45 / p2 (5p2) Multiply both sides by  5p2

9 p2 = 45 .5 Simplify

9 p2 = 225 Simplify

9 p2 ÷  9 = 225 ÷ 9 Divide both sides by 9

p2 = 25

The perimeter of the smaller pentagon is 25 millimetres.

Let’s practice!