Triangle angle-sum Theorem

The sum of the interior angle measures of a triangle is 180°.

A triangle is the smallest polygon that has three sides and three interior angles. In this article, we are going to discuss the angle sum property

Angle Sum Property of a Triangle Theorem

In the given triangle, ∆ABC, AB, BC, and CA represent three sides. A, B and C are the three vertices and ∠ABC, ∠BCA and ∠CAB are three interior angles of ∆ABC.

Angle sum property of triangle states that the sum of interior angles of a triangle is 180°.

Proof: 

Consider a ∆ABC, as shown in the figure below. To prove the above property of triangles, draw a line PQ parallel to the side BC of the given triangle.

Since PQ is a straight line, it can be concluded that:

∠PAB + ∠BAC + ∠QAC = 180° ………(1)

Since PQ||BC and AB, AC are transversals,

Therefore, ∠QAC = ∠ACB (a pair of alternate angles)

Also, ∠PAB = ∠CBA (a pair of alternate angles)

Substituting the value of ∠QAC and ∠PAB in equation (1),

∠ACB + ∠BAC + ∠CBA= 180°

Thus, the sum of the interior angles of a triangle is 180°.

Learn with an example

The diagram shows a triangle

Y =_________°

First, look at the interior angle measures in the triangle.

Set the sum of the interior angle measures of the triangle equal to 180°. Solve for Y.

68° + Y + 49° = 180°

Y + 117° = 180° Combine like terms

Y = 63° Subtract 117° from both sides

So , Y = 63°

The diagram shows a triangle

Y =_________°

First, look at the interior angle measures in the triangle.

Set the sum of the interior angle measures of the triangle equal to 180°. Solve for X.

30° + 74° + X = 180°

X+ 104° = 180° Combine like terms

X = 76° Subtract 104° from both sides

So , X = 76°

The diagram shows a triangle.

Y =_________°

First, look at the interior angle measures in the triangle.

Set the sum of the interior angle measures of the triangle equal to 180°. Solve for Y.

48° + Y + 44° = 180°

Y + 92° = 180° Combine like terms

Y = 88° Subtract 92° from both sides

So , Y = 88°

let’s practice!