Factorise quadratics: special cases
key notes:
Factorizing a difference of squares:
a2–b2=(a+b)(a–b)
a2+2ab+b2=(a+b)2
a2–2ab+b2=(a–b)2
Learn with an example
Factorise.
25z2–16=___________
Notice that 25z2–16 is a difference of squares, because it can be written in the form a2–b2, where a is 5z and b is 4.
a2–b2
(5z)2–42
25z2–16
Now use the formula for factorising a difference of squares.
a2–b2=(a+b)(a–b)
(5z)2–42=(5z+4)(5z–4)
25z2–16=(5z+4)(5z–4)
The factorised form of 25z2–16 is (5z+4)(5z–4).
Finally, check your work.
(5z+4)(5z–4)
25z2+20z–20z–16Apply the distributive property (FOIL)
25z2–16
Yes, 25z2–16=(5z+4)(5z–4).
Factorise.
f2–8f+16=_________________
Notice that f2–8f+16 is a perfect square trinomial because it can be written in the form a2–2ab+b2, where a is f and b is 4.
a2–2ab+b2
f2–2f . 4+42
f2–8f+16
Now use the formula for factorising perfect square trinomials.
a2–2ab+b2=(a–b)2
f2–2f . 4+42=(f–4)2
f2–8f+16=(f–4)2
The factorised form of f2–8f+16 is (f–4)2.
Finally, check your work.
(f–4)2
(f–4)(f–4)Expand
f2–4f–4f+16 Apply the distributive property (FOIL)
f2–8f+16
Yes, f2–8f+16=(f–4)2.
Factorise.
q2–4q+4=____________________
Notice that q2–4q+4 is a perfect square trinomial because it can be written in the form a2–2ab+b2, where a is q and b is 2.
a2–2ab+b2
q2–2q . 2+22
q2–4q+4
Now use the formula for factorising perfect square trinomials.
a2–2ab+b2=(a–b)2
q2–2q . 2+22=(q–2)2
q2–4q+4=(q–2)2
The factorised form of q2–4q+4 is (q–2)2.
Finally, check your work.
(q–2)2
(q–2)(q–2)Expand
q2–2q–2q+4Apply the distributive property (FOIL)
q2–4q+4
Yes, q2–4q+4=(q–2)2.
let’s practice!